what is the domain of the function $y = sqrt3{x - 1}$?\n$-infty<x<infty$\n$-1<x<infty$\n$0leq…
what is the domain of the function $y = sqrt3{x - 1}$?\n$-infty<x<infty$\n$-1<x<infty$\n$0leq x<infty$\n$1leq x<infty$
Answer
Answer:
A. $-\infty<x<\infty$
Explanation:
Step1: Recall cube - root function property
The cube - root function $\sqrt[3]{u}$ is defined for all real values of $u$.
Step2: Identify the expression inside the cube - root
In the function $y = \sqrt[3]{x - 1}$, the expression inside the cube - root is $u=x - 1$.
Step3: Determine the domain
Since $x-1$ can be any real number, $x$ can be any real number. So the domain is $-\infty<x<\infty$.