what is the domain of $f(x)=sqrt3{x}$?\nall real numbers\npositive numbers and zero\nall integers\nwhole…

Explanation:

Step1: Recall cube - root function property

The cube - root function $y = \sqrt[3]{x}$ is defined for all real values of $x$. This is because for any real number $a$, there exists a real number $b$ such that $b^{3}=a$. For example, if $x = 8$, then $\sqrt[3]{8}=2$; if $x=-8$, then $\sqrt[3]{-8}=-2$.

Answer:

all real numbers