h(x)=x^{2}+1 k(x)=x - 2\n(h + k)(2)=\ndone\n(h - k)(3)=\ndone\nevaluate 3h(2)+2k(3)=

Explanation:

Step1: Find ((h + k)(2))

First, find ((h + k)(x)=h(x)+k(x)=(x^{2}+1)+(x - 2)=x^{2}+x - 1). Then substitute (x = 2): ((h + k)(2)=2^{2}+2 - 1=4 + 2-1=5).

Step2: Find ((h - k)(3))

Find ((h - k)(x)=h(x)-k(x)=(x^{2}+1)-(x - 2)=x^{2}-x + 3). Then substitute (x = 3): ((h - k)(3)=3^{2}-3 + 3=9).

Step3: Find (3h(2)+2k(3))

First, find (h(2)=2^{2}+1=5), so (3h(2)=3\times5 = 15). Second, find (k(3)=3 - 2=1), so (2k(3)=2\times1=2). Then (3h(2)+2k(3)=15 + 2=17).

Answer:

((h + k)(2)=5) ((h - k)(3)=9) (3h(2)+2k(3)=17)