drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. match each quadratic…

drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. match each quadratic equation with its solution set. 2x² - 32 = 0 4x² - 100 = 0 x² - 55 = 9 x² - 140 = -19 2x² - 18 = 0 {-8, 8} {-4, 4} {-5, 5} {-11, 11}

drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. match each quadratic equation with its solution set. 2x² - 32 = 0 4x² - 100 = 0 x² - 55 = 9 x² - 140 = -19 2x² - 18 = 0 {-8, 8} {-4, 4} {-5, 5} {-11, 11}

Answer

Explanation:

Step1: Solve $2x^{2}-32 = 0$

Add 32 to both sides: $2x^{2}=32$. Then divide by 2: $x^{2}=16$. Take square - roots: $x=\pm4$. So the solution set is ${-4,4}$.

Step2: Solve $4x^{2}-100 = 0$

Add 100 to both sides: $4x^{2}=100$. Divide by 4: $x^{2}=25$. Take square - roots: $x = \pm5$. So the solution set is ${-5,5}$.

Step3: Solve $x^{2}-55 = 9$

Add 55 to both sides: $x^{2}=9 + 55=64$. Take square - roots: $x=\pm8$. So the solution set is ${-8,8}$.

Step4: Solve $x^{2}-140=-19$

Add 140 to both sides: $x^{2}=-19 + 140 = 121$. Take square - roots: $x=\pm11$. So the solution set is ${-11,11}$.

Step5: Solve $2x^{2}-18 = 0$

Add 18 to both sides: $2x^{2}=18$. Divide by 2: $x^{2}=9$. Take square - roots: $x=\pm3$ (not in the given solution sets).

Answer:

${-8,8}\to x^{2}-55 = 9$ ${-4,4}\to2x^{2}-32 = 0$ ${-5,5}\to4x^{2}-100 = 0$ ${-11,11}\to x^{2}-140=-19$