due: february 20 at 3:35 pm\ngrade: 5%\nnew test grade: 22%\ninterpret exponential function…

due: february 20 at 3:35 pm\ngrade: 5%\nnew test grade: 22%\ninterpret exponential function constant\nsimplify nth root radicals (type 2)\nconvert log equation to exponential (numeric)\nexpanding logarithms (level 2)\nscientific calculator\ngraphing calculator\nyvette molina log out\ncopyright ©2026 deltamath.com all rights reserved. terms & policies\nquestion\nthe function $f(t) = 940(0.97)^{30t}$ represents the change in a quantity over $t$ months. what does the constant 0.97 reveal about the rate of change of the quantity?\nanswer attempt 1 out of 2\nthe function is decaying exponentially at a rate of □% every □.\nsubmit answer\nwatch video\nshow examples

due: february 20 at 3:35 pm\ngrade: 5%\nnew test grade: 22%\ninterpret exponential function constant\nsimplify nth root radicals (type 2)\nconvert log equation to exponential (numeric)\nexpanding logarithms (level 2)\nscientific calculator\ngraphing calculator\nyvette molina log out\ncopyright ©2026 deltamath.com all rights reserved. terms & policies\nquestion\nthe function $f(t) = 940(0.97)^{30t}$ represents the change in a quantity over $t$ months. what does the constant 0.97 reveal about the rate of change of the quantity?\nanswer attempt 1 out of 2\nthe function is decaying exponentially at a rate of □% every □.\nsubmit answer\nwatch video\nshow examples

Answer

Explanation:

Step1: Identify decay factor base

The base of the exponential term is $0.97$.

Step2: Calculate decay rate per period

Subtract the base from 1 to find the decay rate: $1 - 0.97 = 0.03$, or $3%$.

Step3: Match period to exponent

The exponent is $30t$, where $t$ is in months, so the period is $\frac{1}{30}$ months (or 1 day, since 30 days ≈ 1 month).

Answer:

The function is decaying exponentially at a rate of $3%$ every $\frac{1}{30}$ months (or 1 day).