2(r + 6) \neq 4(r + 4)

Explanation:

Step1: Expand both sides

$2(r + 6)=2r+12$ and $4(r + 4)=4r + 16$. So the equation becomes $2r+12=4r + 16$.

Step2: Move the terms with $r$ to one - side

Subtract $2r$ from both sides: $2r+12-2r=4r + 16-2r$, which simplifies to $12 = 2r+16$.

Step3: Isolate the term with $r$

Subtract 16 from both sides: $12-16=2r+16 - 16$, getting $-4 = 2r$.

Step4: Solve for $r$

Divide both sides by 2: $\frac{-4}{2}=\frac{2r}{2}$, so $r=-2$.

Answer:

$r=-2$