what is the equation of the asymptote of the graph of the function ( y = 16(0.75)^{x} )?\nmove the correct…

what is the equation of the asymptote of the graph of the function ( y = 16(0.75)^{x} )?\nmove the correct answer to each box. not all answers will be used.\n( x ) ( y ) ( 0 ) ( 0.75 ) ( 12 ) ( 16 )\n( square=square )

what is the equation of the asymptote of the graph of the function ( y = 16(0.75)^{x} )?\nmove the correct answer to each box. not all answers will be used.\n( x ) ( y ) ( 0 ) ( 0.75 ) ( 12 ) ( 16 )\n( square=square )

Answer

Explanation:

Step1: Recall the general form of an exponential function

The general form of an exponential function is (y = a(b)^{x}+k). For the function (y = 16(0.75)^{x}), it can be written as (y=16(0.75)^{x}+0).

Step2: Determine the horizontal asymptote

For an exponential function of the form (y = a(b)^{x}+k) ((b\neq1)), the horizontal asymptote is (y = k). Here, (k = 0).

Answer:

(y=0)