which equation is the inverse of y = 16x² + 1?\no y = ±√(x/16 - 1)\no y = ±√(x - 1)/16\no y = ±√x/4 - 1/4\no…
which equation is the inverse of y = 16x² + 1?\no y = ±√(x/16 - 1)\no y = ±√(x - 1)/16\no y = ±√x/4 - 1/4\no y = ±√(x - 1)/4
Answer
Explanation:
Step1: Swap x and y
$x = 16y^{2}+1$
Step2: Solve for y
$x - 1=16y^{2}$ $y^{2}=\frac{x - 1}{16}$ $y=\pm\sqrt{\frac{x - 1}{16}}=\pm\frac{\sqrt{x - 1}}{4}$
Answer:
$y=\pm\frac{\sqrt{x - 1}}{4}$ (corresponding to the last option)