the equation of a linear function in point - slope form is $y - y_1=m(x - x_1)$. harold correctly wrote the…

the equation of a linear function in point - slope form is $y - y_1=m(x - x_1)$. harold correctly wrote the equation $y = 3(x - 7)$ using a point and the slope. which point did harold use?\n(7,3)\n(0,7)\n(7,0)\n(3,7)

the equation of a linear function in point - slope form is $y - y_1=m(x - x_1)$. harold correctly wrote the equation $y = 3(x - 7)$ using a point and the slope. which point did harold use?\n(7,3)\n(0,7)\n(7,0)\n(3,7)

Answer

Explanation:

Step1: Recall point - slope form

The point - slope form is $y - y_1=m(x - x_1)$. Harold's equation is $y=3(x - 7)$ which can be written as $y-0 = 3(x - 7)$.

Step2: Identify the point

Comparing $y-0 = 3(x - 7)$ with $y - y_1=m(x - x_1)$, we have $x_1 = 7$ and $y_1=0$. So the point is $(7,0)$.

Answer:

C. $(7,0)$