the equation of a linear function in point - slope form is y - y1 = m(x - x1). harold correctly wrote the…
the equation of a linear function in point - slope form is y - y1 = m(x - x1). harold correctly wrote the equation y = 3(x - 7) using a point and the slope. which point did harold use? (7, 3) (0, 7) (7, 0) (3, 7)
Answer
Explanation:
Step1: Rewrite the given equation in point - slope form
The given equation is $y = 3(x - 7)$. We can rewrite it as $y-0 = 3(x - 7)$. The point - slope form is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.
Step2: Identify the point
Comparing $y-0 = 3(x - 7)$ with $y - y_1=m(x - x_1)$, we have $x_1 = 7$ and $y_1=0$. So the point is $(7,0)$.
Answer:
(7, 0)