which equation has real zeros corresponding to the x - intercepts of the graph?\n$y = \\log_3(x)-1$\n$y =…

Explanation:

Step1: Recall zero - definition

The real zeros of a function are the values of (x) for which (y = 0).

Step2: Analyze (y=\log_3(x)-1)

Set (y = 0), then (\log_3(x)-1=0), so (\log_3(x)=1). By the definition of logarithms (x = 3^1=3).

Step3: Analyze (y = 3^x-3)

Set (y = 0), then (3^x-3=0), so (3^x=3), and (x = 1).

Step4: Analyze (y=-3^{(x - 1)}+3)

Set (y = 0), then (-3^{(x - 1)}+3=0), so (3^{(x - 1)}=3), and (x-1 = 1), (x=2).

Step5: Analyze (y=\log_3(2x)-2)

Set (y = 0), then (\log_3(2x)-2=0), so (\log_3(2x)=2). By the definition of logarithms (2x=3^2 = 9), (x=\frac{9}{2}=4.5).

From the graph, the (x) - intercept seems to be at (x = 3).

Answer:

(y=\log_3(x)-1)