which equation represents the line that passes through (-6, 7) and (-3, 6)?\no $y = -\\frac{1}{3}x + 9$\no…

which equation represents the line that passes through (-6, 7) and (-3, 6)?\no $y = -\\frac{1}{3}x + 9$\no $y = -\\frac{1}{3}x + 5$\no $y = -3x - 11y$\no $y = -3x + 25$

which equation represents the line that passes through (-6, 7) and (-3, 6)?\no $y = -\\frac{1}{3}x + 9$\no $y = -\\frac{1}{3}x + 5$\no $y = -3x - 11y$\no $y = -3x + 25$

Answer

Answer:

A. $y = -\frac{1}{3}x + 5$

Explanation:

Step1: Calculate the slope

The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let $(x_1,y_1)=(-6,7)$ and $(x_2,y_2)=(-3,6)$. Then $m=\frac{6 - 7}{-3-(-6)}=\frac{-1}{3}=-\frac{1}{3}$.

Step2: Use point - slope form

The point - slope form is $y - y_1=m(x - x_1)$. Using the point $(-3,6)$ and $m = -\frac{1}{3}$, we have $y - 6=-\frac{1}{3}(x + 3)$.

Step3: Simplify the equation

Expand the right - hand side: $y-6=-\frac{1}{3}x - 1$. Add 6 to both sides: $y=-\frac{1}{3}x+5$.