which equation represents a line that passes through $(4,\frac{1}{3})$ and has a slope of $\frac{3}{4}$?\n$y…

which equation represents a line that passes through $(4,\frac{1}{3})$ and has a slope of $\frac{3}{4}$?\n$y - \frac{3}{4}=\frac{1}{3}(x - 4)$\n$y-\frac{1}{3}=\frac{3}{4}(x - 4)$\n$y-\frac{1}{3}=4(x-\frac{3}{4})$\n$y - 4=\frac{3}{4}(x-\frac{1}{3})$

which equation represents a line that passes through $(4,\frac{1}{3})$ and has a slope of $\frac{3}{4}$?\n$y - \frac{3}{4}=\frac{1}{3}(x - 4)$\n$y-\frac{1}{3}=\frac{3}{4}(x - 4)$\n$y-\frac{1}{3}=4(x-\frac{3}{4})$\n$y - 4=\frac{3}{4}(x-\frac{1}{3})$

Answer

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.

Step2: Identify values

Given the point $(4,\frac{1}{3})$ and slope $m = \frac{3}{4}$, so $x_1 = 4$, $y_1=\frac{1}{3}$, and $m=\frac{3}{4}$.

Step3: Substitute values

Substitute into the point - slope form: $y-\frac{1}{3}=\frac{3}{4}(x - 4)$.

Answer:

$y-\frac{1}{3}=\frac{3}{4}(x - 4)$ (the second option)