which equation represents a line with slope of $-\frac{1}{4}$ and y - intercept of $\frac{5}{4}$?\na $x + 4y…

which equation represents a line with slope of $-\frac{1}{4}$ and y - intercept of $\frac{5}{4}$?\na $x + 4y = 5$\nb $x - 4y = 5$\nc $4x - y = - 5$\nd $4x + y = - 5$

which equation represents a line with slope of $-\frac{1}{4}$ and y - intercept of $\frac{5}{4}$?\na $x + 4y = 5$\nb $x - 4y = 5$\nc $4x - y = - 5$\nd $4x + y = - 5$

Answer

Answer:

A. $x + 4y=5$

Explanation:

Step1: Write the slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the $y$-intercept. Given $m=-\frac{1}{4}$ and $b = \frac{5}{4}$, the equation is $y=-\frac{1}{4}x+\frac{5}{4}$.

Step2: Rearrange the equation

Multiply through by 4 to get $4y=-x + 5$. Then add $x$ to both sides, resulting in $x + 4y=5$.