which equation results from cross - multiplying?\n$\frac{15}{a^{2}-1}=\frac{5}{2a - 2}$\n$15(a^{2}-1)=5(2a…

which equation results from cross - multiplying?\n$\frac{15}{a^{2}-1}=\frac{5}{2a - 2}$\n$15(a^{2}-1)=5(2a - 2)$\n$15(2a - 2)=5(a^{2}-1)$\n$15(a^{2}-1)(2a - 2)=5(2a - 2)(a^{2}-1)$

which equation results from cross - multiplying?\n$\frac{15}{a^{2}-1}=\frac{5}{2a - 2}$\n$15(a^{2}-1)=5(2a - 2)$\n$15(2a - 2)=5(a^{2}-1)$\n$15(a^{2}-1)(2a - 2)=5(2a - 2)(a^{2}-1)$

Answer

Explanation:

Step1: Recall cross - multiplication rule

For $\frac{a}{b}=\frac{c}{d}$, it becomes $a\times d = c\times b$.

Step2: Apply rule to given equation

Given $\frac{15}{a^{2}-1}=\frac{5}{2a - 2}$, cross - multiplying gives $15\times(2a - 2)=5\times(a^{2}-1)$.

Answer:

$15(2a - 2)=5(a^{2}-1)$