which equation shows the point - slope form of the line that passes through (3, 2) and has a slope of…

which equation shows the point - slope form of the line that passes through (3, 2) and has a slope of $\frac{1}{3}$?\n$y + 2=\frac{1}{3}(x + 3)$\n$y - 2=\frac{1}{3}(x - 3)$\n$y + 3=\frac{1}{3}(x + 2)$\n$y - 3=\frac{1}{3}(x - 2)$

which equation shows the point - slope form of the line that passes through (3, 2) and has a slope of $\frac{1}{3}$?\n$y + 2=\frac{1}{3}(x + 3)$\n$y - 2=\frac{1}{3}(x - 3)$\n$y + 3=\frac{1}{3}(x + 2)$\n$y - 3=\frac{1}{3}(x - 2)$

Answer

Explanation:

Step1: Recall point - slope formula

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.

Step2: Identify values of $x_1$, $y_1$ and $m$

Given the point $(3,2)$ and slope $m = \frac{1}{3}$, so $x_1 = 3$, $y_1=2$ and $m=\frac{1}{3}$.

Step3: Substitute values into formula

Substitute $x_1 = 3$, $y_1 = 2$ and $m=\frac{1}{3}$ into $y - y_1=m(x - x_1)$, we get $y - 2=\frac{1}{3}(x - 3)$.

Answer:

B. $y - 2=\frac{1}{3}(x - 3)$