which equation shows the quadratic formula used correctly to solve 5x² + 3x - 4 = 0 for x?\nx=\frac{-3pmsqrt{…

which equation shows the quadratic formula used correctly to solve 5x² + 3x - 4 = 0 for x?\nx=\frac{-3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)}\nx=\frac{3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)}\nx=\frac{3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)}\nx=\frac{-3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)}

which equation shows the quadratic formula used correctly to solve 5x² + 3x - 4 = 0 for x?\nx=\frac{-3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)}\nx=\frac{3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)}\nx=\frac{3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)}\nx=\frac{-3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)}

Answer

Explanation:

Step1: Recall quadratic formula

For a quadratic equation $ax^{2}+bx + c=0$, the quadratic formula is $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$.

Step2: Identify coefficients

In the equation $5x^{2}+3x - 4=0$, $a = 5$, $b = 3$, and $c=-4$.

Step3: Substitute coefficients

Substitute $a = 5$, $b = 3$, and $c=-4$ into the quadratic formula: $x=\frac{-3\pm\sqrt{(3)^{2}-4(5)(-4)}}{2(5)}$

Answer:

$x=\frac{-3\pm\sqrt{(3)^{2}-4(5)(-4)}}{2(5)}$ (the first - option)