which equation shows the quadratic formula used correctly to solve (5x^{2}+3x - 4 = 0) for…

which equation shows the quadratic formula used correctly to solve (5x^{2}+3x - 4 = 0) for (x)?\n(x=\frac{-3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)})\n(x=\frac{3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)})\n(x=\frac{3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)})\n(x=\frac{-3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)})

which equation shows the quadratic formula used correctly to solve (5x^{2}+3x - 4 = 0) for (x)?\n(x=\frac{-3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)})\n(x=\frac{3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)})\n(x=\frac{3pmsqrt{(3)^{2}-4(5)(-4)}}{2(5)})\n(x=\frac{-3pmsqrt{(3)^{2}+4(5)(-4)}}{2(5)})

Answer

Explanation:

Step1: Recall the quadratic formula

For a quadratic equation (ax^{2}+bx + c=0), the quadratic formula is (x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}).

Step2: Identify (a), (b), and (c)

In the equation (5x^{2}+3x - 4=0), (a = 5), (b=3), and (c=-4).

Step3: Substitute into the quadratic formula

Substitute (a = 5), (b = 3), and (c=-4) into (x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}). We get (x=\frac{-3\pm\sqrt{(3)^{2}-4(5)(-4)}}{2(5)}).

Answer:

(x=\frac{-3\pm\sqrt{(3)^{2}-4(5)(-4)}}{2(5)}) (the first option)