which equation has solutions of 6 and -6?\n$x^{2}+36 = 0$\n$x^{2}-12x + 36 = 0$\n$x^{2}+12x - 36 =…
which equation has solutions of 6 and -6?\n$x^{2}+36 = 0$\n$x^{2}-12x + 36 = 0$\n$x^{2}+12x - 36 = 0$\n$x^{2}-36 = 0$
Answer
Explanation:
Step1: Recall the zero - product property
If (x = a) and (x = b) are the solutions of a quadratic equation, then the equation can be written as ((x - a)(x - b)=0). Here (a = 6) and (b=-6).
Step2: Expand the equation
((x - 6)(x+6)=x^{2}+6x-6x - 36).
Step3: Simplify the expanded equation
Combining like - terms, (x^{2}+6x-6x - 36=x^{2}-36). So the quadratic equation with solutions (x = 6) and (x=-6) is (x^{2}-36 = 0).
Answer:
(x^{2}-36 = 0)