which equation, when solved, results in a different value of x than the other three?\n-\\frac{7}{8}x…

which equation, when solved, results in a different value of x than the other three?\n-\\frac{7}{8}x - \\frac{3}{4}=20\n\\frac{3}{4}+\\frac{7}{8}x=-20\n-7(\\frac{1}{8})x - \\frac{3}{4}=20\n-\\frac{7}{8}(-\\frac{8}{7})x - \\frac{3}{4}=20(-\\frac{8}{7})

which equation, when solved, results in a different value of x than the other three?\n-\\frac{7}{8}x - \\frac{3}{4}=20\n\\frac{3}{4}+\\frac{7}{8}x=-20\n-7(\\frac{1}{8})x - \\frac{3}{4}=20\n-\\frac{7}{8}(-\\frac{8}{7})x - \\frac{3}{4}=20(-\\frac{8}{7})

Answer

Explanation:

Step1: Solve the first equation

Add $\frac{3}{4}$ to both sides of $-\frac{7}{8}x-\frac{3}{4}=20$: $-\frac{7}{8}x = 20+\frac{3}{4}=\frac{80 + 3}{4}=\frac{83}{4}$. Then multiply both sides by $-\frac{8}{7}$, so $x=-\frac{83}{4}\times\frac{8}{7}=-\frac{166}{7}$.

Step2: Solve the second equation

Subtract $\frac{3}{4}$ from both sides of $\frac{3}{4}+\frac{7}{8}x=-20$: $\frac{7}{8}x=-20 - \frac{3}{4}=\frac{-80 - 3}{4}=-\frac{83}{4}$. Then multiply both sides by $\frac{8}{7}$, so $x=-\frac{83}{4}\times\frac{8}{7}=-\frac{166}{7}$.

Step3: Solve the third equation

The equation $-7(\frac{1}{8})x-\frac{3}{4}=20$ is equivalent to $-\frac{7}{8}x-\frac{3}{4}=20$, which is the same as the first - equation, and $x = -\frac{166}{7}$.

Step4: Solve the fourth equation

Simplify $-\frac{7}{8}(-\frac{8}{7})x-\frac{3}{4}=20(-\frac{8}{7})$. The left - hand side simplifies to $x-\frac{3}{4}$, and the right - hand side is $-\frac{160}{7}$. Then add $\frac{3}{4}$ to both sides: $x=-\frac{160}{7}+\frac{3}{4}=\frac{-640 + 21}{28}=-\frac{619}{28}$.

Answer:

$-\frac{7}{8}(-\frac{8}{7})x-\frac{3}{4}=20(-\frac{8}{7})$