which equation is true?\n$9x^{2}-25=(3x - 5)(3x - 5)$\n$9x^{2}-25=(3x - 5)(3x + 5)$\n$9x^{2}-25=-(3x + 5)(3x…

which equation is true?\n$9x^{2}-25=(3x - 5)(3x - 5)$\n$9x^{2}-25=(3x - 5)(3x + 5)$\n$9x^{2}-25=-(3x + 5)(3x + 5)$\n$9x^{2}-25=-(3x + 5)(3x - 5)$

which equation is true?\n$9x^{2}-25=(3x - 5)(3x - 5)$\n$9x^{2}-25=(3x - 5)(3x + 5)$\n$9x^{2}-25=-(3x + 5)(3x + 5)$\n$9x^{2}-25=-(3x + 5)(3x - 5)$

Answer

Explanation:

Step1: Recall difference - of - squares formula

The difference - of - squares formula is (a^{2}-b^{2}=(a - b)(a + b)). In the expression (9x^{2}-25), we can rewrite (9x^{2}=(3x)^{2}) and (25 = 5^{2}). So (9x^{2}-25=(3x)^{2}-5^{2}).

Step2: Apply the formula

Using the difference - of - squares formula (a^{2}-b^{2}=(a - b)(a + b)) with (a = 3x) and (b = 5), we get ((3x)^{2}-5^{2}=(3x - 5)(3x + 5)).

Answer:

(9x^{2}-25=(3x - 5)(3x + 5)), so the second option is true.