which equation can be used to represent \six added to twice the sum of a number and four is equal to one…

which equation can be used to represent \six added to twice the sum of a number and four is equal to one - half of the difference of three and the number\?\n$6 + 2(x + 4)=\frac{1}{2}(3 - x)$\n$6 + 2(x + 4)=\frac{1}{2}(x - 3)$\n$(6 + 2)(x + 4)=\frac{1}{2}(3 - x)$\n$(6 + 2)(x + 4)=\frac{1}{2}(x - 3)$

which equation can be used to represent \six added to twice the sum of a number and four is equal to one - half of the difference of three and the number\?\n$6 + 2(x + 4)=\frac{1}{2}(3 - x)$\n$6 + 2(x + 4)=\frac{1}{2}(x - 3)$\n$(6 + 2)(x + 4)=\frac{1}{2}(3 - x)$\n$(6 + 2)(x + 4)=\frac{1}{2}(x - 3)$

Answer

Explanation:

Step1: Analyze "twice the sum of a number and four"

Let the number be (x). The sum of a number and four is (x + 4), and twice this sum is (2(x + 4)). Then "six added to twice the sum of a number and four" is (6+2(x + 4)).

Step2: Analyze "one - half of the difference of three and the number"

The difference of three and the number is (3 - x), and one - half of this difference is (\frac{1}{2}(3 - x)).

Answer:

(6 + 2(x + 4)=\frac{1}{2}(3 - x)) (the first option)