which equation has an a - value of -2, a b - value of 1, and a c - value of 3?\n0=-2x^{2}+x + 3\n0=2x^{2}+x…

which equation has an a - value of -2, a b - value of 1, and a c - value of 3?\n0=-2x^{2}+x + 3\n0=2x^{2}+x + 3\n0=-2x^{2}+3\n0=2x^{2}-x + 3
Answer
Explanation:
Step1: Recall quadratic - form
The general form of a quadratic equation is $ax^{2}+bx + c=0$.
Step2: Check each option
For the equation $0=-2x^{2}+x + 3$, we have $a=-2$, $b = 1$, and $c = 3$. For the equation $0=2x^{2}+x + 3$, $a = 2$, not - 2. For the equation $0=-2x^{2}+3$, $b = 0$, not 1. For the equation $0=2x^{2}-x + 3$, $a = 2$, not - 2.
Answer:
$0=-2x^{2}+x + 3$