which equation has an a - value of -2, a b - value of 1, and a c - value of 3?\n0=-2x^{2}+x + 3\n0=2x^{2}+x…

which equation has an a - value of -2, a b - value of 1, and a c - value of 3?\n0=-2x^{2}+x + 3\n0=2x^{2}+x + 3\n0=-2x^{2}+3\n0=2x^{2}-x + 3

which equation has an a - value of -2, a b - value of 1, and a c - value of 3?\n0=-2x^{2}+x + 3\n0=2x^{2}+x + 3\n0=-2x^{2}+3\n0=2x^{2}-x + 3

Answer

Explanation:

Step1: Recall quadratic - form

The general form of a quadratic equation is $ax^{2}+bx + c=0$.

Step2: Check each option

For the equation $0=-2x^{2}+x + 3$, we have $a=-2$, $b = 1$, and $c = 3$. For the equation $0=2x^{2}+x + 3$, $a = 2$, not - 2. For the equation $0=-2x^{2}+3$, $b = 0$, not 1. For the equation $0=2x^{2}-x + 3$, $a = 2$, not - 2.

Answer:

$0=-2x^{2}+x + 3$