which equation has an a - value of 1, a b - value of - 3, and a c - value of - 5?\n0=-3x - 5+x^{2}\n0=x - 3…

Explanation:

Step1: Recall quadratic form

The general form of a quadratic equation is $ax^{2}+bx + c=0$.

Step2: Rearrange option A

For $0=-3x - 5+x^{2}$, rewrite it as $x^{2}-3x - 5=0$. Here $a = 1$, $b=-3$, $c=-5$.

Step3: Rearrange option B

For $0=x - 3-5x^{2}$, rewrite it as $-5x^{2}+x - 3=0$, so $a=-5$, $b = 1$, $c=-3$.

Step4: Rearrange option C

For $0=3x - 5-x^{2}$, rewrite it as $-x^{2}+3x - 5=0$, so $a=-1$, $b = 3$, $c=-5$.

Step5: Rearrange option D

For $0=-3x + 5-x^{2}$, rewrite it as $-x^{2}-3x + 5=0$, so $a=-1$, $b=-3$, $c = 5$.

Answer:

A. $0=-3x - 5+x^{2}$