which equations are true for x = -2 and x = 2? select two options\n$x^{2}-4 = 0$\n$x^{2}=-4$\n$3x^{2}+12 =…

which equations are true for x = -2 and x = 2? select two options\n$x^{2}-4 = 0$\n$x^{2}=-4$\n$3x^{2}+12 = 0$\n$4x^{2}=16$\n$2(x - 2)^{2}=0$

which equations are true for x = -2 and x = 2? select two options\n$x^{2}-4 = 0$\n$x^{2}=-4$\n$3x^{2}+12 = 0$\n$4x^{2}=16$\n$2(x - 2)^{2}=0$

Answer

Explanation:

Step1: Check $x^{2}-4 = 0$

Substitute $x = 2$: $2^{2}-4=4 - 4=0$. Substitute $x=-2$: $(-2)^{2}-4 = 4 - 4=0$.

Step2: Check $x^{2}=-4$

Substitute $x = 2$: $2^{2}=4\neq - 4$. Substitute $x=-2$: $(-2)^{2}=4\neq - 4$.

Step3: Check $3x^{2}+12 = 0$

Substitute $x = 2$: $3\times2^{2}+12=3\times4 + 12=12 + 12=24\neq0$. Substitute $x=-2$: $3\times(-2)^{2}+12=3\times4+12=24\neq0$.

Step4: Check $4x^{2}=16$

Substitute $x = 2$: $4\times2^{2}=4\times4 = 16$. Substitute $x=-2$: $4\times(-2)^{2}=4\times4 = 16$.

Step5: Check $2(x - 2)^{2}=0$

Substitute $x = 2$: $2\times(2 - 2)^{2}=2\times0=0$. Substitute $x=-2$: $2\times(-2 - 2)^{2}=2\times(-4)^{2}=2\times16 = 32\neq0$.

Answer:

$x^{2}-4 = 0$, $4x^{2}=16$