an equilateral triangle has a perimeter of $15x^{3}+33x^{5}$ feet. what is the length of each side?\n$x^{3}$…

Explanation:

Step1: Recall equilateral triangle property

In an equilateral triangle, perimeter $P = 3s$, where $s$ is the side - length. So, $s=\frac{P}{3}$.

Step2: Divide the given perimeter by 3

Given $P = 15x^{3}+33x^{5}$, then $s=\frac{15x^{3}+33x^{5}}{3}$. Using the distributive property of division $\frac{a + b}{c}=\frac{a}{c}+\frac{b}{c}$, we have $s=\frac{15x^{3}}{3}+\frac{33x^{5}}{3}$.

Step3: Simplify each term

$\frac{15x^{3}}{3}=5x^{3}$ and $\frac{33x^{5}}{3}=11x^{5}$. So, $s = 5x^{3}+11x^{5}$.

Answer:

D. $5x^{3}+11x^{5}$ feet