which is equivalent to $log_2n = 4$?\n$log n=\frac{log2}{4}$\n$n = \frac{log2}{log4}$\n$n=log4cdotlog2$\n$log…

which is equivalent to $log_2n = 4$?\n$log n=\frac{log2}{4}$\n$n = \frac{log2}{log4}$\n$n=log4cdotlog2$\n$log n = 4log2$

which is equivalent to $log_2n = 4$?\n$log n=\frac{log2}{4}$\n$n = \frac{log2}{log4}$\n$n=log4cdotlog2$\n$log n = 4log2$

Answer

Explanation:

Step1: Use the definition of logarithms

By the definition of logarithms, if $\log_{a}b = c$, then $b=a^{c}$. Given $\log_{2}n = 4$, we have $n = 2^{4}$.

Step2: Apply the power - rule of logarithms

The power - rule of logarithms states that $\log m^{k}=k\log m$. Take the common logarithm (base - 10) of both sides of $n = 2^{4}$. We get $\log n=\log(2^{4})$.

Step3: Simplify the right - hand side

Using the power - rule $\log(2^{4}) = 4\log2$. So, $\log n=4\log2$.

Answer:

$\log n = 4\log2$ (the fourth option)