evaluate (2 - 5i)(p + q)(i) when p = 2 and q = 5i.\n\n29i\n29i - 20\n-21i\n29

evaluate (2 - 5i)(p + q)(i) when p = 2 and q = 5i.\n\n29i\n29i - 20\n-21i\n29
Answer
Explanation:
Step1: Substitute values of p and q
Substitute (p = 2) and (q = 5i) into ((p + q)): (p+q=2 + 5i)
Step2: Multiply ((2 - 5i)) and ((p + q))
((2-5i)(2 + 5i)=2^2-(5i)^2) (using ((a - b)(a + b)=a^2 - b^2)) (=4-25i^2) Since (i^2=-1), we have (4-25\times(-1)=4 + 25=29)
Step3: Multiply the result by (i)
(29\times i=29i)
Answer:
(29i)