evaluate the expression when ( x = - 4 ).\n( x ^ { 2 } + 6 x + 3 )

evaluate the expression when ( x = - 4 ).\n( x ^ { 2 } + 6 x + 3 )
Answer
Explanation:
Step1: Substitute (x = - 4) into the expression
[ \begin{align*} &(-4)^2+6\times(-4)+3\ \end{align*} ]
Step2: Calculate each term
- Calculate ((-4)^2): ((-4)^2=(-4)\times(-4) = 16)
- Calculate (6\times(-4)): (6\times(-4)=-24) The expression becomes (16-24 + 3)
Step3: Perform addition and subtraction
[ \begin{align*} &16-24+3\ =&(16 + 3)-24\ =&19-24\ =&-5 \end{align*} ]
Answer:
(-5)