evaluate $\frac{1}{4}c + 3d$ when $c = 6$ and $d = 7$.

Explanation:

Step1: Substitute the values of c and d

Substitute $c = 6$ and $d = 7$ into $\frac{1}{4}c+3d$. We get $\frac{1}{4}\times6 + 3\times7$.

Step2: Calculate $\frac{1}{4}\times6$

$\frac{1}{4}\times6=\frac{6}{4}=\frac{3}{2}=1.5$.

Step3: Calculate $3\times7$

$3\times7 = 21$.

Step4: Add the two results

$1.5+21=22.5$.

Answer:

$22.5$