evaluate $\frac{3}{7}r+\frac{5}{8}s$ when $r = 14$ and $s = 8$.

evaluate $\frac{3}{7}r+\frac{5}{8}s$ when $r = 14$ and $s = 8$.

evaluate $\frac{3}{7}r+\frac{5}{8}s$ when $r = 14$ and $s = 8$.

Answer

Explanation:

Step1: Substitute values of r and s

Substitute $r = 14$ and $s = 8$ into $\frac{3}{7}r+\frac{5}{8}s$. We get $\frac{3}{7}\times14+\frac{5}{8}\times8$.

Step2: Calculate $\frac{3}{7}\times14$

$\frac{3}{7}\times14 = 3\times2=6$.

Step3: Calculate $\frac{5}{8}\times8$

$\frac{5}{8}\times8 = 5$.

Step4: Add the results

$6 + 5=11$.

Answer:

11