evaluate \\frac{y}{2}+x^{2}+4+\\sqrt{z}+y^{3} if x = 7, y = 2, and z = 4. a) 66 b) 64 c) 49 d) 15

evaluate \\frac{y}{2}+x^{2}+4+\\sqrt{z}+y^{3} if x = 7, y = 2, and z = 4. a) 66 b) 64 c) 49 d) 15

evaluate \\frac{y}{2}+x^{2}+4+\\sqrt{z}+y^{3} if x = 7, y = 2, and z = 4. a) 66 b) 64 c) 49 d) 15

Answer

Explanation:

Step1: Substitute the values

Substitute (x = 7), (y = 2), and (z = 4) into the expression (\frac{y}{2}+x^{2}+4+\sqrt{z}+y^{3}). We get (\frac{2}{2}+7^{2}+4+\sqrt{4}+2^{3}).

Step2: Calculate each term

Calculate (\frac{2}{2}=1).
Calculate (7^{2}=49).
Calculate (\sqrt{4} = 2).
Calculate (2^{3}=8). The expression becomes (1 + 49+4 + 2+8).

Step3: Sum the terms

(1+49 = 50), (50+4=54), (54 + 2=56), (56+8=64).

Answer:

B. 64