in exercises 3 - 10, evaluate the function when x = -2, 0, and 5. (see example 1.) 3. f(x)=x + 6 4. g(x)=3x…

in exercises 3 - 10, evaluate the function when x = -2, 0, and 5. (see example 1.) 3. f(x)=x + 6 4. g(x)=3x 5. h(x)=-2x + 9 6. r(x)=-x - 7 7. p(x)=-3 + 4x 8. b(x)=18 - 0.5x 9. v(x)=12 - 2x - 5 10. n(x)=-1 - x + 4 11. interpreting function notation let c(t) be the number of customers in a restaurant t hours after 8 a.m. explain the meaning of each statement. (see example 2.)

in exercises 3 - 10, evaluate the function when x = -2, 0, and 5. (see example 1.) 3. f(x)=x + 6 4. g(x)=3x 5. h(x)=-2x + 9 6. r(x)=-x - 7 7. p(x)=-3 + 4x 8. b(x)=18 - 0.5x 9. v(x)=12 - 2x - 5 10. n(x)=-1 - x + 4 11. interpreting function notation let c(t) be the number of customers in a restaurant t hours after 8 a.m. explain the meaning of each statement. (see example 2.)

Answer

3. $f(x)=x + 6$

Explanation:

Step1: Substitute $x=-2$

$f(-2)=-2 + 6=4$

Step2: Substitute $x = 0$

$f(0)=0+6=6$

Step3: Substitute $x = 5$

$f(5)=5 + 6=11$

Answer:

When $x=-2$, $f(-2)=4$; when $x = 0$, $f(0)=6$; when $x = 5$, $f(5)=11$

4. $g(x)=3x$

Explanation:

Step1: Substitute $x=-2$

$g(-2)=3\times(-2)=-6$

Step2: Substitute $x = 0$

$g(0)=3\times0=0$

Step3: Substitute $x = 5$

$g(5)=3\times5 = 15$

Answer:

When $x=-2$, $g(-2)=-6$; when $x = 0$, $g(0)=0$; when $x = 5$, $g(5)=15$

5. $h(x)=-2x + 9$

Explanation:

Step1: Substitute $x=-2$

$h(-2)=-2\times(-2)+9=4 + 9=13$

Step2: Substitute $x = 0$

$h(0)=-2\times0+9=9$

Step3: Substitute $x = 5$

$h(5)=-2\times5+9=-10 + 9=-1$

Answer:

When $x=-2$, $h(-2)=13$; when $x = 0$, $h(0)=9$; when $x = 5$, $h(5)=-1$

6. $r(x)=-x - 7$

Explanation:

Step1: Substitute $x=-2$

$r(-2)=-(-2)-7=2-7=-5$

Step2: Substitute $x = 0$

$r(0)=-0-7=-7$

Step3: Substitute $x = 5$

$r(5)=-5-7=-12$

Answer:

When $x=-2$, $r(-2)=-5$; when $x = 0$, $r(0)=-7$; when $x = 5$, $r(5)=-12$

7. $p(x)=-3 + 4x$

Explanation:

Step1: Substitute $x=-2$

$p(-2)=-3+4\times(-2)=-3-8=-11$

Step2: Substitute $x = 0$

$p(0)=-3+4\times0=-3$

Step3: Substitute $x = 5$

$p(5)=-3+4\times5=-3 + 20=17$

Answer:

When $x=-2$, $p(-2)=-11$; when $x = 0$, $p(0)=-3$; when $x = 5$, $p(5)=17$

8. $b(x)=18-0.5x$

Explanation:

Step1: Substitute $x=-2$

$b(-2)=18-0.5\times(-2)=18 + 1=19$

Step2: Substitute $x = 0$

$b(0)=18-0.5\times0=18$

Step3: Substitute $x = 5$

$b(5)=18-0.5\times5=18-2.5 = 15.5$

Answer:

When $x=-2$, $b(-2)=19$; when $x = 0$, $b(0)=18$; when $x = 5$, $b(5)=15.5$

9. First simplify $v(x)=12-2x - 5=7-2x$

Explanation:

Step1: Substitute $x=-2$

$v(-2)=7-2\times(-2)=7 + 4=11$

Step2: Substitute $x = 0$

$v(0)=7-2\times0=7$

Step3: Substitute $x = 5$

$v(5)=7-2\times5=7-10=-3$

Answer:

When $x=-2$, $v(-2)=11$; when $x = 0$, $v(0)=7$; when $x = 5$, $v(5)=-3$

10. First simplify $n(x)=-1-x + 4=3-x$

Explanation:

Step1: Substitute $x=-2$

$n(-2)=3-(-2)=3 + 2=5$

Step2: Substitute $x = 0$

$n(0)=3-0=3$

Step3: Substitute $x = 5$

$n(5)=3-5=-2$

Answer:

When $x=-2$, $n(-2)=5$; when $x = 0$, $n(0)=3$; when $x = 5$, $n(5)=-2$