which explains how to find the radius of a circle whose equation is in the form $x^{2}+y^{2}=z$?\nthe radius…

which explains how to find the radius of a circle whose equation is in the form $x^{2}+y^{2}=z$?\nthe radius is the constant term, z.\nthe radius is the constant term, z, divided by 2.\nthe radius is the square root of the constant term, z.\nthe radius is the square of the constant term, z.

which explains how to find the radius of a circle whose equation is in the form $x^{2}+y^{2}=z$?\nthe radius is the constant term, z.\nthe radius is the constant term, z, divided by 2.\nthe radius is the square root of the constant term, z.\nthe radius is the square of the constant term, z.

Answer

Explanation:

Step1: Recall circle - equation formula

The standard form of the equation of a circle with center at the origin ((0,0)) is ((x - 0)^2+(y - 0)^2=r^2), which simplifies to (x^{2}+y^{2}=r^{2}), where (r) is the radius of the circle.

Step2: Compare with given equation

Given the equation (x^{2}+y^{2}=z), by comparing (x^{2}+y^{2}=r^{2}) and (x^{2}+y^{2}=z), we can see that (r^{2}=z).

Step3: Solve for (r)

To find (r), we take the square - root of both sides of the equation (r^{2}=z). So (r = \sqrt{z}) (we consider the positive square root since the radius is a non - negative quantity).

Answer:

The radius is the square root of the constant term, (z).