what is the exponent?\ny = (x + 4)(x + 3)^2(x + 1)^?
what is the exponent?\ny = (x + 4)(x + 3)^2(x + 1)^?
Answer
Explanation:
Step1: Analyze graph behavior at root
The graph touches the x - axis at (x=-1). For a polynomial (y = a(x - r_1)^{n_1}(x - r_2)^{n_2}\cdots), when the graph touches the x - axis at a root (r), the exponent (n) of the corresponding factor ((x - r)) is even.
Step2: Check options
Among the options 1, 3, and 2, since the graph touches the x - axis at (x=-1) (corresponding to factor ((x + 1))), the exponent must be even. So the exponent of ((x + 1)) is 2.
Answer:
C. 2