which expression is equivalent to $(3x^{2}-7)$?\n$(2x^{2}-11)-(x^{2}+4)$\n$(5x^{2}-6)-(2x^{2}-1)$\n$(10x^{2}…

which expression is equivalent to $(3x^{2}-7)$?\n$(2x^{2}-11)-(x^{2}+4)$\n$(5x^{2}-6)-(2x^{2}-1)$\n$(10x^{2}-4)-(7x^{2}+3)$\n$(15x^{2}+8)-(18x^{2}+1)$

which expression is equivalent to $(3x^{2}-7)$?\n$(2x^{2}-11)-(x^{2}+4)$\n$(5x^{2}-6)-(2x^{2}-1)$\n$(10x^{2}-4)-(7x^{2}+3)$\n$(15x^{2}+8)-(18x^{2}+1)$

Answer

Explanation:

Step1: Simplify option 1

$(2x^{2}-11)-(x^{2}+4)=2x^{2}-11 - x^{2}-4=x^{2}-15$

Step2: Simplify option 2

$(5x^{2}-6)-(2x^{2}-1)=5x^{2}-6 - 2x^{2}+1 = 3x^{2}-5$

Step3: Simplify option 3

$(10x^{2}-4)-(7x^{2}+3)=10x^{2}-4 - 7x^{2}-3=3x^{2}-7$

Step4: Simplify option 4

$(15x^{2}+8)-(18x^{2}+1)=15x^{2}+8 - 18x^{2}-1=-3x^{2}+7$

Answer:

$(10x^{2}-4)-(7x^{2}+3)$