which expression is equivalent to the following complex fraction?\n$\frac{2 - \frac{1}{y}}{3+\frac{1}{y}}$\n$…

which expression is equivalent to the following complex fraction?\n$\frac{2 - \frac{1}{y}}{3+\frac{1}{y}}$\n$\frac{3y + 1}{2y-1}$\n$\frac{(2y - 1)(3y + 1)}{y^{2}}$\n$\frac{y^{2}}{(2y - 1)(3y + 1)}$\n$\frac{2y-1}{3y + 1}$

which expression is equivalent to the following complex fraction?\n$\frac{2 - \frac{1}{y}}{3+\frac{1}{y}}$\n$\frac{3y + 1}{2y-1}$\n$\frac{(2y - 1)(3y + 1)}{y^{2}}$\n$\frac{y^{2}}{(2y - 1)(3y + 1)}$\n$\frac{2y-1}{3y + 1}$

Answer

Explanation:

Step1: Simplify numerator and denominator

Simplify (2-\frac{1}{y}) to (\frac{2y - 1}{y}) and (3+\frac{1}{y}) to (\frac{3y + 1}{y}). So the complex - fraction (\frac{2-\frac{1}{y}}{3+\frac{1}{y}}) becomes (\frac{\frac{2y - 1}{y}}{\frac{3y + 1}{y}}).

Step2: Divide by a fraction

Dividing by a fraction is the same as multiplying by its reciprocal. So (\frac{\frac{2y - 1}{y}}{\frac{3y + 1}{y}}=\frac{2y - 1}{y}\times\frac{y}{3y + 1}).

Step3: Cancel out common factors

The (y) in the numerator and denominator cancels out, and we get (\frac{2y - 1}{3y + 1}).

Answer:

(\frac{2y - 1}{3y + 1})