which expression is equivalent to $\frac{mn^{2}}{mn + m^{2}n^{2}}$?\n$\frac{1}{n + m}$\n$\frac{n}{1 +…

which expression is equivalent to $\frac{mn^{2}}{mn + m^{2}n^{2}}$?\n$\frac{1}{n + m}$\n$\frac{n}{1 + m^{2}n^{2}}$\n$\frac{n}{1+mn}$\n$\frac{1}{m^{2}n}$

which expression is equivalent to $\frac{mn^{2}}{mn + m^{2}n^{2}}$?\n$\frac{1}{n + m}$\n$\frac{n}{1 + m^{2}n^{2}}$\n$\frac{n}{1+mn}$\n$\frac{1}{m^{2}n}$

Answer

Answer:

C. $\frac{n}{1 + mn}$

Explanation:

Step1: Factor out common terms

Factor out $mn$ from the denominator $mn + m^{2}n^{2}$. We get $mn(1+mn)$. So the original expression $\frac{mn^{2}}{mn + m^{2}n^{2}}$ becomes $\frac{mn^{2}}{mn(1 + mn)}$.

Step2: Simplify the fraction

Cancel out the common factors $mn$ in the numerator and the denominator. $\frac{mn^{2}}{mn(1 + mn)}=\frac{n}{1 + mn}$.