factor: $f^{3}-8$\na $(f + 2)(f^{2}-2f + 4)$\nb $(f - 2)^{3}$\nc $(f - 2)(f^{2}+2f + 4)$\nd $(f…

factor: $f^{3}-8$\na $(f + 2)(f^{2}-2f + 4)$\nb $(f - 2)^{3}$\nc $(f - 2)(f^{2}+2f + 4)$\nd $(f - 2)(f^{2}+4)$\n$a^{2}+2ab + b^{2}=(a + b)^{2}$\n$a^{2}-2ab + b^{2}=(a - b)^{2}$\n$a^{3}+b^{3}=(a + b)(a^{2}-ab + b^{2})$\n$a^{3}-b^{3}=(a - b)(a^{2}+ab + b^{2})$

factor: $f^{3}-8$\na $(f + 2)(f^{2}-2f + 4)$\nb $(f - 2)^{3}$\nc $(f - 2)(f^{2}+2f + 4)$\nd $(f - 2)(f^{2}+4)$\n$a^{2}+2ab + b^{2}=(a + b)^{2}$\n$a^{2}-2ab + b^{2}=(a - b)^{2}$\n$a^{3}+b^{3}=(a + b)(a^{2}-ab + b^{2})$\n$a^{3}-b^{3}=(a - b)(a^{2}+ab + b^{2})$

Answer

Answer:

C. $(f - 2)(f^{2}+2f + 4)$

Explanation:

Step1: Identify the formula

We use the formula $a^{3}-b^{3}=(a - b)(a^{2}+ab + b^{2})$. Here $a = f$ and $b = 2$ since $8=2^{3}$.

Step2: Substitute values

Substitute $a=f$ and $b = 2$ into the formula. We get $f^{3}-8=(f - 2)(f^{2}+2f + 4)$.