factor: 8 + x³\na (2 + x)(4 - 2x + x²)\nb (2 + x)³\nc (2 - x)(4 + 2x + x²)\nd (2 + x)(4 + x²)
factor: 8 + x³\na (2 + x)(4 - 2x + x²)\nb (2 + x)³\nc (2 - x)(4 + 2x + x²)\nd (2 + x)(4 + x²)
Answer
Explanation:
Step1: Identify cube - sum form
We know that (8 + x^{3}) is in the form of (a^{3}+b^{3}), where (a = 2) (since (2^{3}=8)) and (b=x).
Step2: Apply sum - of - cubes formula
The sum - of - cubes formula is (a^{3}+b^{3}=(a + b)(a^{2}-ab + b^{2})). Substituting (a = 2) and (b=x) into the formula, we get ((2 + x)(2^{2}-2x+x^{2})=(2 + x)(4-2x + x^{2})).
Answer:
A. ((2 + x)(4-2x + x^{2}))