factor $x^{3}+2x^{2}+x$ completely.\n$(x + 1)^{2}$\n$x(x^{2}+1)$\n$x(x + 1)^{2}$\ndone
factor $x^{3}+2x^{2}+x$ completely.\n$(x + 1)^{2}$\n$x(x^{2}+1)$\n$x(x + 1)^{2}$\ndone
Answer
Explanation:
Step1: Factor out the common factor
First, factor out the common factor $x$ from the expression $x^{3}+2x^{2}+x$. We get $x(x^{2}+2x + 1)$.
Step2: Factor the quadratic expression
The quadratic expression $x^{2}+2x + 1$ is a perfect - square trinomial. According to the formula $(a + b)^2=a^{2}+2ab + b^{2}$, where $a=x$ and $b = 1$, so $x^{2}+2x + 1=(x + 1)^{2}$.
Answer:
$x(x + 1)^{2}$