factor $-7x^{3}+21x^{2}+3x - 9$ by grouping. what is the resulting expression?\n$(3 - 7x)(x^{2}-3)$\n$(7x…

factor $-7x^{3}+21x^{2}+3x - 9$ by grouping. what is the resulting expression?\n$(3 - 7x)(x^{2}-3)$\n$(7x - 3)(3 + x^{2})$\n$(3 - 7x^{2})(x - 3)$\n$(7x^{2}-3)(3 + x)$

factor $-7x^{3}+21x^{2}+3x - 9$ by grouping. what is the resulting expression?\n$(3 - 7x)(x^{2}-3)$\n$(7x - 3)(3 + x^{2})$\n$(3 - 7x^{2})(x - 3)$\n$(7x^{2}-3)(3 + x)$

Answer

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: ((-7x^{3}+21x^{2})+(3x - 9))

Step2: Factor out the GCF from each group

For (-7x^{3}+21x^{2}), the GCF is (-7x^{2}), so (-7x^{2}(x - 3)). For (3x - 9), the GCF is (3), so (3(x - 3))

Step3: Factor out the common binomial factor

We have (-7x^{2}(x - 3)+3(x - 3)=(x - 3)(-7x^{2}+3)=(3 - 7x^{2})(x - 3))

Answer:

((3 - 7x^{2})(x - 3)) (the third option)