which is a factor of $x^{2}+8x - 48$?\n$(x - 6)$\n$(x + 4)$\n$(x - 16)$\n$(x + 12)$

which is a factor of $x^{2}+8x - 48$?\n$(x - 6)$\n$(x + 4)$\n$(x - 16)$\n$(x + 12)$

which is a factor of $x^{2}+8x - 48$?\n$(x - 6)$\n$(x + 4)$\n$(x - 16)$\n$(x + 12)$

Answer

Explanation:

Step1: Factor the quadratic expression

We need to factor (x^{2}+8x - 48). We look for two numbers that multiply to (-48) and add up to (8). The numbers are (12) and (- 4) since (12\times(-4)=-48) and (12+( - 4)=8). So (x^{2}+8x - 48=(x + 12)(x-4)).

Answer:

D. ((x + 12))