what is the factored form of $n^{2}-25$?\n$(n - 25)(n - 1)$\n$(n - 5)(n + 5)$\n$(n + 5)(n + 5)$\n$(n - 25)(n…
what is the factored form of $n^{2}-25$?\n$(n - 25)(n - 1)$\n$(n - 5)(n + 5)$\n$(n + 5)(n + 5)$\n$(n - 25)(n + 1)$
Answer
Answer:
B. $(n - 5)(n + 5)$
Explanation:
Step1: Recall difference - of - squares formula
The difference - of - squares formula is $a^{2}-b^{2}=(a - b)(a + b)$.
Step2: Identify $a$ and $b$ in the given expression
In the expression $n^{2}-25$, we have $a = n$ and $b = 5$ since $n^{2}$ is the square of $n$ and $25=5^{2}$.
Step3: Apply the formula
Substituting $a = n$ and $b = 5$ into the difference - of - squares formula, we get $n^{2}-25=(n - 5)(n + 5)$.