what is the factored form of $x^{2}-4x - 5$?\n$(x + 5)(x - 1)$\n$(x + 5)(x + 1)$\n$(x - 5)(x - 1)$\n$(x…

what is the factored form of $x^{2}-4x - 5$?\n$(x + 5)(x - 1)$\n$(x + 5)(x + 1)$\n$(x - 5)(x - 1)$\n$(x - 5)(x + 1)$

what is the factored form of $x^{2}-4x - 5$?\n$(x + 5)(x - 1)$\n$(x + 5)(x + 1)$\n$(x - 5)(x - 1)$\n$(x - 5)(x + 1)$

Answer

Explanation:

Step1: Find two numbers

We need two numbers that multiply to - 5 and add up to - 4. The numbers are - 5 and 1 since (-5)×1=-5 and - 5 + 1=-4.

Step2: Write in factored form

For a quadratic of the form (ax^{2}+bx + c) (here (a = 1), (b=-4), (c = - 5)), the factored form is ((x + m)(x + n)) where (m) and (n) are the two numbers. So (x^{2}-4x - 5=(x - 5)(x+1)).

Answer:

D. ((x - 5)(x + 1))