what is the factored form of $6n^{4}-24n^{3}+18n$?\n$6n(n^{4}+4n^{3}+3n)$\n$6n(n^{4}-4n^{3}+3n)$\n$6n(n^{3}-4…
what is the factored form of $6n^{4}-24n^{3}+18n$?\n$6n(n^{4}+4n^{3}+3n)$\n$6n(n^{4}-4n^{3}+3n)$\n$6n(n^{3}-4n^{2}+3)$\n$6n(n^{3}+4n^{2}+3)$
Answer
Explanation:
Step1: Find the GCF of terms
The GCF of $6n^{4}$, $- 24n^{3}$ and $18n$ is $6n$.
Step2: Factor out the GCF
$\frac{6n^{4}}{6n}=n^{3}$, $\frac{-24n^{3}}{6n}=-4n^{2}$, $\frac{18n}{6n} = 3$. So $6n^{4}-24n^{3}+18n=6n(n^{3}-4n^{2}+3)$.
Answer:
C. $6n(n^{3}-4n^{2}+3)$