what is the factored form of $x^{2}-6x - 16$?\n$(x - 4)(x - 2)$\n$(x + 4)(x - 2)$\n$(x - 2)(x + 8)$\n$(x…

Explanation:

Step1: Analyze the quadratic form

For a quadratic (x^2+bx + c), we need two numbers (m) and (n) such that (m + n=b) and (m\times n = c). Here (b=-6) and (c=-16).

Step2: Find the two numbers

We need two numbers (m) and (n) where (m + n=-6) and (m\times n=-16). The numbers are (-8) and (2) since (-8+2=-6) and (-8\times2=-16).

Step3: Write the factored form

Using the formula (x^2+(m + n)x+mn=(x + m)(x + n)), we get (x^2-6x - 16=(x-8)(x + 2))

Answer:

((x - 8)(x + 2)) (the fourth option)