what is the factorization of 49b² - 81?\n(7b - 9)(7b - 9)\n(7b - 9)(7b + 9)\n(7b² - 9)(7b² - 9)\n(7b²…
what is the factorization of 49b² - 81?\n(7b - 9)(7b - 9)\n(7b - 9)(7b + 9)\n(7b² - 9)(7b² - 9)\n(7b² - 9)(7b² + 9)
Answer
Explanation:
Step1: Recognize difference - of - squares
The expression $49b^{2}-81$ is in the form $a^{2}-b^{2}$, where $a = 7b$ ($(7b)^{2}=49b^{2}$) and $b = 9$ ($9^{2}=81$).
Step2: Apply difference - of - squares formula
The difference - of - squares formula is $a^{2}-b^{2}=(a - b)(a + b)$. Substituting $a = 7b$ and $b = 9$ into the formula, we get $(7b-9)(7b + 9)$.
Answer:
B. $(7b - 9)(7b + 9)$