which is the factorization of 8x² + 13x - 6?\n(8x - 3)(x + 2)\n(x - 6)(8x + 1)\n(2x - 2)(4x + 3)\n(4x…

which is the factorization of 8x² + 13x - 6?\n(8x - 3)(x + 2)\n(x - 6)(8x + 1)\n(2x - 2)(4x + 3)\n(4x - 1)(2x + 6)

which is the factorization of 8x² + 13x - 6?\n(8x - 3)(x + 2)\n(x - 6)(8x + 1)\n(2x - 2)(4x + 3)\n(4x - 1)(2x + 6)

Answer

Explanation:

Step1: Expand each option

For option A: $(8x - 3)(x + 2)=8x\times x+8x\times2-3\times x - 3\times2=8x^{2}+16x-3x - 6=8x^{2}+13x - 6$. For option B: $(x - 6)(8x + 1)=x\times8x+x\times1-6\times8x-6\times1=8x^{2}+x - 48x - 6=8x^{2}-47x - 6$. For option C: $(2x - 2)(4x + 3)=2x\times4x+2x\times3-2\times4x-2\times3=8x^{2}+6x - 8x - 6=8x^{2}-2x - 6$. For option D: $(4x - 1)(2x + 6)=4x\times2x+4x\times6-1\times2x-1\times6=8x^{2}+24x - 2x - 6=8x^{2}+22x - 6$.

Answer:

A. $(8x - 3)(x + 2)$