faelyn grouped the terms and factored the gcf out of the groups of the polynomial $6x^{4}-8x^{2}+3x^{2}+4$…

faelyn grouped the terms and factored the gcf out of the groups of the polynomial $6x^{4}-8x^{2}+3x^{2}+4$. her work is shown. step 1: $(6x^{4}-8x^{2})+(3x^{2}+4)$ step 2: $2x^{2}(3x^{2}-4)+1(3x^{2}+4)$ faelyn noticed that she does not have a common factor. which accurately describes what faelyn should do next? faelyn should realize that her work shows that the polynomial is prime. faelyn should go back and regroup the terms in step 1 as $(6x^{4}+3x^{2})-(8x^{2}+4)$. in step 2, faelyn should factor only $2x$ out of the first expression. faelyn should factor out a negative from one of the groups so the binomials will be the same.

faelyn grouped the terms and factored the gcf out of the groups of the polynomial $6x^{4}-8x^{2}+3x^{2}+4$. her work is shown. step 1: $(6x^{4}-8x^{2})+(3x^{2}+4)$ step 2: $2x^{2}(3x^{2}-4)+1(3x^{2}+4)$ faelyn noticed that she does not have a common factor. which accurately describes what faelyn should do next? faelyn should realize that her work shows that the polynomial is prime. faelyn should go back and regroup the terms in step 1 as $(6x^{4}+3x^{2})-(8x^{2}+4)$. in step 2, faelyn should factor only $2x$ out of the first expression. faelyn should factor out a negative from one of the groups so the binomials will be the same.

Answer

Brief Explanations:

A prime polynomial cannot be factored over the set of integers. Since after factoring out the GCF from the grouped - terms, there is no further common factor to factor out, the polynomial is prime.

Answer:

Faelyn should realize that her work shows that the polynomial is prime.